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x^2-50x=-525
We move all terms to the left:
x^2-50x-(-525)=0
We add all the numbers together, and all the variables
x^2-50x+525=0
a = 1; b = -50; c = +525;
Δ = b2-4ac
Δ = -502-4·1·525
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-20}{2*1}=\frac{30}{2} =15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+20}{2*1}=\frac{70}{2} =35 $
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